Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Sulfurous acid (H2SO3) is a weak, unstable acid that exists primarily in aqueous solution. It is formed when sulfur dioxide (SO2) dissolves in water. Sulfurous acid decomposes rapidly and is not commonly found in pure form. It plays a role in various chemical reactions and environmental processes, such as acid rain formation.

Let's dive into drawing the Lewis structure of H2SO3:
Step 1: Identify the Central Atom: Sulfur (S) is the central atom in H2SO3 because it's less electronegative than oxygen (O) and hydrogen (H).
Step 2: Calculate Total Valence Electrons: Sulfur contributes 6 valence electrons, each oxygen contributes 6, and each hydrogen contributes 1, giving a total of 6 + (3 × 6) + (2 × 1) = 26 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each oxygen atom to the central sulfur atom with a single bond (line) and distribute the remaining electrons as lone pairs around each oxygen atom. Place two hydrogen atoms connected to the sulfur atom with single bonds.
Step 4: Fulfill the Octet Rule: Ensure each oxygen atom has 8 electrons (2 lone pairs and 1 bonding pair), and the sulfur atom has 6 electrons (2 lone pairs and 4 bonding pairs). Hydrogen atoms each have 2 electrons (1 bonding pair).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.

The structure of sulfurous acid comprises a central sulfur atom surrounded by three oxygen atoms, including one oxygen atom bonded to the sulfur atom with a double bond. The molecular geometry of H2SO3 will be bent. There will be a 107.8-degree angle between the O-S-O bonds.
This theory addresses electron repulsion and the need for compounds to adopt stable forms. In H2SO3, there are two single bonds and one double bond between sulfur and oxygen atoms. The double bond involves a sigma bond and a pi bond. Although sulfur has only four valence orbitals, the Lewis structure suggests five bond pairs, implying the use of sp3 hybridization for the sulfur atom.
The Lewis structure suggests that H2SO3 adopts a bent geometry. In this arrangement, the three oxygen atoms are positioned around the central sulfur atom, forming a bent structure. This geometry minimizes electron-electron repulsion, resulting in a stable configuration.
The orbitals involved, and the bonds produced during the interaction of sulfur and oxygen molecules, will be examined to determine the hybridization of sulfurous acid. 3s, 3px, 3py, and 3pz are the orbitals involved. The sulfur atom, which is the central atom in its ground state, will have the 3s23p4 configuration in its formation.
The electron pairs in the 3s and 3px orbitals become unpaired in the excited state, and one of each pair is promoted to the unoccupied 3py and 3pz orbitals. All four half-filled orbitals (one 3s, two 3p) hybridize now, resulting in the production of four sp3 hybrid orbitals.
The bond angle in H2SO3 is approximately 107.8 degrees. This angle arises from the bent geometry of the molecule, where the three oxygen atoms are positioned around the central sulfur atom. The bond length in H2SO3 is approximately 160 pm for the S-O single bond and approximately 150 pm for the S=O double bond.
| Sulfurous Acid (CAS 7790-99-0) | |
| Molecular formula | H2SO3 |
| Molecular shape | bent |
| Polarity | Polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 107.8 degrees |
| Bond length | Approximately 160 pm (S-O single bond), 150 pm (S=O double bond) |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of sulfurous acid (H2SO3), the Lewis structure shows sulfur at the center bonded to three oxygen atoms. H2SO3 has a bent geometry, where the three oxygen atoms are asymmetrically arranged around the sulfur atom. This asymmetry results in a net dipole moment, making H2SO3 a polar molecule.
To calculate the total bond energy of H2SO3, first, look up the bond energy for a single sulfur-oxygen (S-O) bond, which is approximately 343 kJ/mol, and the sulfur-oxygen double bond (S=O) energy, which is approximately 799 kJ/mol. H2SO3 has two S-O single bonds and one S=O double bond. The total bond energy can be calculated by summing these values: (2 × 343 kJ/mol) + 799 kJ/mol = 1485 kJ/mol.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of H2SO3, each sulfur-oxygen bond is either a single bond (bond order = 1) or a double bond (bond order = 2). For the S-O single bonds, the bond order is 1, and for the S=O double bond, the bond order is 2.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In H2SO3, each sulfur atom has four electron groups around it, corresponding to the two S-O single bonds, one S=O double bond, and one lone pair on the sulfur atom.
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In H2SO3, sulfur is surrounded by two S-O single bonds (represented by lines in the Lewis structure), one S=O double bond, and one lone pair (two dots). Each oxygen atom is represented by two pairs of dots (lone pairs) and one bonding pair with sulfur. The dots help visualize how electrons are shared or paired between atoms.
![]() |
![]() |
![]() |