
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Antimony hexabromide (SbBr6-) is a compound consisting of one antimony atom bonded to six bromine atoms. It is a solid under standard conditions and is known for its unique properties, including its high reactivity and stability. SbBr6- is often used in various chemical reactions and applications due to its distinctive bonding and structural characteristics. What is the SbBr? Lewis structure molecular geometry?

Let's dive into drawing the Lewis structure of SbBr6-:
Step 1: Identify the Central Atom: Antimony (Sb) is the central atom in SbBr6- because it's less electronegative than bromine.
Step 2: Calculate Total Valence Electrons: Antimony contributes 5 valence electrons, and each bromine contributes 7, giving a total of 5 + (6 x 7) = 47 valence electrons. Because it's an anion, you add a negatively charged electron, you get 48 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each bromine atom to the central antimony atom with a single bond (line) and distribute the remaining electrons as lone pairs around each bromine atom.
Step 4: Fulfill the Octet Rule: Ensure each bromine atom has 8 electrons (2 lone pairs and 1 bonding pair), and the antimony atom has 12 electrons (2 lone pairs and 6 bonding pairs).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.
The structure of Antimony hexabromide comprises a central Antimony atom around which 12 electrons or 6 electron pairs are present and no lone pairs, therefore the molecular geometry of SbBr6- will be octahedral. There will be a 90-degree angle between the Br-Sb-Br bonds.

This theory addresses electron repulsion and the need for compounds to adopt stable forms. In SbBr6-, six sigma bonds form between antimony and bromine, with three lone pairs on each bromine atom. Although antimony has only five valence orbitals, the Lewis structure suggests six bond pairs, implying the use of d-orbitals in this hypervalent complex. However, advanced calculations reveal the electronic structure actually consists of four delocalized bonds across all seven atoms, rather than six distinct bonds involving d-orbitals.
The Lewis structure suggests that SbBr6- adopts an octahedral geometry. In this arrangement, the six bromine atoms are symmetrically positioned around the central antimony atom, forming six bond pairs. This geometry minimizes electron-electron repulsion, resulting in a stable configuration.
The orbitals involved, and the bonds produced during the interaction of Antimony and bromine molecules, will be examined to determine the hybridization of Antimony hexabromide. 5s, 5px, 5py, 5pz, 5dx2-y2, and 5dz2 are the orbitals involved. The Antimony atom, which is the central atom in its ground state, will have the 5s25p3 configuration in its formation.
The electron pairs in the 5s and 5p orbitals become unpaired in the excited state, and one of each pair is promoted to the unoccupied 5dx2-y2 and 5dz2 orbitals. All six half-filled orbitals (one 5s, three 5p, and two 5d) hybridize now, resulting in the production of six sp3d2 hybrid orbitals.
The bond angle in SbBr6- is approximately 90 degrees. This angle arises from the octahedral geometry of the molecule, where the six bromine atoms are positioned at the vertices of a regular octahedron, resulting in 90-degree bond angles between adjacent bromine atoms. The bond length in SbBr6- is approximately 254 pm.
| Antimony Hexabromide | |
| Molecular formula | SbBr6- |
| Molecular shape | Octahedral |
| Polarity | nonpolar |
| Hybridization | sp3d2 hybridization |
| Bond Angle | 90 degrees |
| Bond length | 254 pm |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of antimony hexabromide (SbBr6-), the Lewis structure shows antimony at the center bonded to six bromine atoms. SbBr6- has an octahedral geometry, where the six bromine atoms are symmetrically arranged around the antimony atom. Although the Sb-Br bonds are polar, the symmetry of the molecule causes the dipole moments to cancel out, making SbBr6- a nonpolar molecule.
To calculate the total bond energy of SbBr6-, first, look up the bond energy for a single antimony-bromine (Sb-Br) bond, which is approximately 240 kJ/mol. SbBr6- has six Sb-Br bonds, so you multiply the bond energy of one Sb-Br bond by the number of bonds. This gives a total bond energy of 1440 kJ/mol for SbBr6-. This value represents the energy required to break all the Sb-Br bonds in one mole of SbBr6- molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of SbBr6-, each antimony-bromine bond is a single bond, so the bond order for each Sb-Br bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but SbBr6- does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In SbBr6-, each antimony atom has six electron groups around it, corresponding to the six Sb-Br bonds (six bonding pairs and no lone pairs on antimony).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In SbBr6-, antimony is surrounded by six bonding pairs (represented by lines in the Lewis structure) and each bromine atom is represented by three pairs of dots (lone pairs) and one bonding pair with antimony. The dots help visualize how electrons are shared or paired between atoms.
![]() |
![]() |
![]() |